If equation of a plane is given 4x+2y+12z=7 then x,y & z intercepts will be
74, 72 & 712
We know the equation of a plane in intercept form which is xa+yb+zc=1
a,b and c are the intercepts made by the plane on x,y and z axes respectively.
In the question the given equation is not in the intercept form, so we’ll convert it into intercept form and then compare.
4x+2y+12z=7
On dividing the equation by 7
4x7+2y7+12z7=1
or x(74)+y(72)+z(712)=1
On comparing it with the standard intercept form we’ll get -
a=74, b=72, c=712
Thus the intercept on x , y & z axes will be
74, 72&712 respectively.