Question

If equation of line is $\left(y-2\sqrt{3}\right)=\frac{\sqrt{3}+1}{\sqrt{3}-1}\left(x-2\right)$, then find the slope.

Answer 1

We have,

$\left(y-2\sqrt{3}\right)=\frac{\sqrt{3}+1}{\sqrt{3}-1}\left(x-2\right)$

We know that

$\left(y-y_1\right)=m\left(x-x_1\right)$

Where $m$ is a slope.

So,

$m=\frac{\sqrt{3}+1}{\sqrt{3}-1}$

Hence, this is the answer.