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Question

# If equation of the parabola is (6x+8y−5)2=60(8x−6y+9), then

A
Equation of axis of the parabola is 6x+8y5=0
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B
Equation of tangent at vertex of the parabola is 6x+8y5=0
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C
Length of latus rectum is 32 units
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D
Length of latus rectum is 6 units
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Solution

## The correct options are A Equation of axis of the parabola is 6x+8y−5=0 D Length of latus rectum is 6 units(6x+8y−5)2=60(8x−6y+9) ⇒(6x+8y−5√62+82)2=6×(8x−6y+9√82+62) On comparing with (Distance from axis)2=L.L.R.(distance from T.V.), equation of axis of the parabola is 6x+8y−5=0 equation of tangent at vertex of the parabola is 8x−6y+9=0 Length of latus rectum (L.L.R.)=6 units

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