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Question

If equation x2+ax+a+1=0 has integrals roots then sum of possible integral values of "a" is

A
2
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B
5
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C
4
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D
0
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Solution

The correct option is C 4
x2+ax+a+1=0roots(x1,x2)2a±a24a42forintegralrootstherootsshouldberemovedso,ontryingvalueofaweget1,and5so,1+5=4

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