If equations bx2+acx+b2c=0 and cx2+abx+b2c=0 have a common root, (where a,b,c are nonzero distinct real numbers), then which of the following is/are correct
A
ac+ab+ba=0
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B
ab+ac+ca=0
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C
1bc2+1a2c+1cb2=0
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D
1ac2+1ba2+1cb2=0
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Solution
The correct options are A1bc2+1a2c+1cb2=0 Dac+ab+ba=0 On solving, we get common root, α=a condition of common root, a2b+a2c+b2c=0 ........(i) On dividing equation (i) by abc, we get ac+ab+ba=0 On dividing equation (i) by a2b2c2, we get 1bc2+1cb2+1a2c=0