The correct option is B Sum of all possible common roots is 0.
x7+ax5−1=0 ...(1)
Clearly, eqn. (1) does not have x=0 as a root.
And x6+ax4−4x=0
So, multiplying by x,
x7+ax5−4x2=0 ...(2)
Equation (1)−(2),
4x2=1
⇒x=±12
Sum of all possible common roots =0.
If x=12 is a solution,
then (12)7+a(12)5−1=0
⇒1+4a−128=0
⇒a=1274
If x=−12 is a solution,
then (−12)7+a(−12)5−1=0
⇒a=−1294
Sum of possible values of a is −12.