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Electrolysis and Electrolytes

If equivalent...

Question

If equivalent conductance of 1M benzoic acid is $12.8 {o h m}^{- 1} {c m}^{2}$ and if the conductance of benzoate ion and $H^{- 1}$ ion are 42 and $288.42 {o h m}^{- 1} {c m}^{2}$ respectively. Its degree of dissolution is:

A

39%

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B

3.9%

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C

0.35%

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D

0.039%

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Solution

The correct option is C 3.9%
$Λ_{m (C_{6} H_{5} C O O H)}^{0} = Λ_{(C_{6} H_{5} C O O^{-})}^{0} + Λ_{(H^{+})}^{0}$
$= 42 + 288.42 = 330.42 n o w w e h a v e, α = \frac{Λ_{m}^{c}}{Λ_{m}^{0}} = \frac{12.8}{330.42} = 3.9$

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