If equivalent weight of $S$ of $S O_{2}$ is $8$ then equivalent weight of $S$ in $S O_{3}$ is

\frac{8 \times 2}{3}

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\frac{8 \times 3}{2}

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8 \times 2 \times 3

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\frac{2 \times 3}{8}

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Solution

The correct option is A $\frac{8 \times 2}{3}$
Equivalent Weight $= \frac{M o l e c u l a r w e i g h t}{V a l e n c y}$

For $S$ in $S O_{2} = \frac{32}{4} = 8$

For $S$ in $S O_{3} = \frac{32}{6} = \frac{16}{3} = \frac{8 \times 2}{3}$

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