Question

If equivalent weight of $S$ of $S{O}_2$ is $8$ then equivalent weight of $S$ in $S{O}_3$ is

• A. $\frac{8\times 2}{3}$
• B. $\frac{8\times 3}{2}$
• C. $8\times 2\times 3$
• D. $\frac{2\times 3}{8}$

Answer 1

The correct option is A $\frac{8\times 2}{3}$

Equivalent Weight $=\frac{Molecularweight}{Valency}$

For $S$ in $S{O}_2=\frac{32}{4}=8$

For $S$ in $S{O}_3=\frac{32}{6}=\frac{16}{3}=\frac{8\times 2}{3}$