Question

If error in measurement of radius of a sphere is $1\%$, what will be the error in measurement volume?

• A. $1\%$
• B. $\frac{1}{3}\%$
• C. $3\%$
• D. None of these

Answer 1

Answer: (C)

$3\%$

$Volume=\frac{4\pi R^3}{3}$

$\frac{\Delta V}{V}\times 100=3\frac{\Delta R}{R}\times 100$

$=3\times \frac{1}{100}\times 100$

$=3$

∴Percentage error in volume is $3$%