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Question

If error in measurement of radius of a sphere is 1%, what will be the error in measurement volume?

A
1%
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B
13%
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C
3%
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D
None of these
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Solution

The correct option is D 3%
Volume=4πR33

ΔVV×100=3ΔRR×100

=3×1100×100

=3

∴Percentage error in volume is 3%

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