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Question

If errors of 1% each are made in the base radius and height of a cylinder, then the percentage error in its volume is

A
1%
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B
2%
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C
3%
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D
none of these
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Solution

The correct option is C 3%
Given, percentage error in r is 1%
Δrr=1100
Δr=r100
Also given, percentage error in h is 1%
Δhh=1100
Δh=h100
Now, volume of cylinder V=πr2h
dVdr=π2rh+πr2dhdr
ΔV=π[r2Δh+2rhΔr]
ΔV=π[r2h100+2rhr100]
ΔV=πr2h[3100]
ΔVV=3100
Percentage error in V is 3%

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