Question

If excess of $AgN{O}_3$ solution is added to 100mL of a 0.024 M solution of dichlorobis (ethylene diamine) cobalt (III) chloride. How many moles of $AgCl$ be precipitated?

• A. 0.0012
• B. 0.0016
• C. 0.0024
• D. 0.0048

Answer 1

Answer: (C)

0.0024

$100mL$ of $0.024M=0.0024$ mol of the complex.

Complex is $\left[Co\right(en{)}_{2}C{l}_2]Cl$ and thus, one $C{l}^{-}$ if formed per mol of the complex which gives 1 mole of AgCl.

$\left[Co\right(en{)}_{2}C{l}_2]Cl+A{g}^{+}\to [Co(en{)}_{2}C{l}_2{]}^{+}+AgCl\downarrow$

Hence, AgCl formed $=0.0024$ mol.