If f(0)=0,f′(0)=2 then the derivative of y=f(f(f(f(x))) at x = 0 is
2
8
16
4
y′(x)=f′(f(f(f(x))).f′(f(f(x))).f′(f(x)).f′(x) so y′(0)=f′(f(f(f(0))).f′(f(f(0))).f′(f(0)).f′(0) =(f′(0))4=24=16
Value of 2xy when x=4 and y=0 is