If f:[0,2]→A,f(x)=[x2]−[x]2 is a real valued function, then minimum elements required in set A is (where [.] denotes greatest integer function)
A
(−∞,0]
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B
(−∞,1]
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C
{0,1,2}
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D
N
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Solution
The correct option is C{0,1,2} f(x)=[x2]−[x]2 We know that, x∈[0,2]⇒x2∈[0,4] We have to check for integer values of x2 in [0,4] Now, f(0)=0f(1)=1−1=0 f(√2)=2−1=1f(√3)=3−1=2 f(2)=4−4=0 So, f(x) is function when A={0,1,2}