If f 0- y - y -1- and f x -1- y - f x - f x - y - Then- what is the value of f 1-2 -A- 1B- 4C- 2D- 3

The correct option is B 4f (x + 1, y) = f(x, f(x, y)) Put x = 0, f (1, y) = f(0, f(0, y)) = f(0, y + 1) = y + 1 + 1 = y + 2 Put y = 2, f (1, 2) = 4. ...

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Quantitative Aptitude

Functions

If f 0, y = y...

Question

If f (0, y) = y + 1, and f(x +1, y) = f (x, f(x, y)). Then, what is the value of f(1,2)?

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Solution

The correct option is D 4
f (x + 1, y) = f(x, f(x, y))

Put x = 0, f (1, y) = f(0, f(0, y)) = f(0, y + 1) = y + 1 + 1 = y + 2

Put y = 2, f (1, 2) = 4.

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If f (0, y) = y + 1, and f(x +1, y) = f (x, f(x, y)). Then, what is the value of f(1,2)?

The correct option is D 4f (x + 1, y) = f(x, f(x, y)) Put x = 0, f (1, y) = f(0, f(0, y)) = f(0, y + 1) = y + 1 + 1 = y + 2 Put y = 2, f (1, 2) = 4.

The correct option is D 4
f (x + 1, y) = f(x, f(x, y))

Put x = 0, f (1, y) = f(0, f(0, y)) = f(0, y + 1) = y + 1 + 1 = y + 2

Put y = 2, f (1, 2) = 4.