If f (0, y) = y + 1, and f(x +1, y) = f (x, f(x, y)). Then, what is the value of f(1,2) ? (CAT 2000)

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Solution

The correct option is D 4
SOLN:(d)
f (x + 1, y) = f(x, f(x, y))
put x = 0, f (1, y) = f(0, f(0, y)) = f(0, y + 1)
= y + 1 + 1 = y + 2
Put y = 2, f (1, 2) = 4.

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