If f ={(1, 2), (2, 2), (3, 2), (4,2), (5, 2), (6, 2)}, find the pre-images of 2. Which type of a function is f?

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Solution

f = {(1, 2), (2, 2), (3, 2), (4,2), (5, 2), (6, 2)}

Pre-images of 2 = {1, 2, 3, 4, 5, 6}

All the elements of the domain are mapped to 2 .Therefore f is a constant function.

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If f ={(1, 2), (2, 2), (3, 2), (4,2), (5, 2), (6, 2)}, find the pre-images of 2. Which type of a function is f?

f = {(1, 2), (2, 2), (3, 2), (4,2), (5, 2), (6, 2)} Pre-images of 2 = {1, 2, 3, 4, 5, 6} All the elements of the domain are mapped to 2 .Therefore f is a constant function.

f = {(1, 2), (2, 2), (3, 2), (4,2), (5, 2), (6, 2)}

Pre-images of 2 = {1, 2, 3, 4, 5, 6}

All the elements of the domain are mapped to 2 .Therefore f is a constant function.