If f = {(1, 2), (2, b), (3, c)} is a constant function, find the values of b and c.
As f is a constant function, all the elements of the domain will be mapped to a unique constant value.
f(1) = 2. The constant value is 2.
Therefore b = c = 2.
LMVT says that if y = f(x) be a given function which is ;
a.Continuous in [a,b]
b. Differentiable in (a,b)
Then, f'(c) = f(b)−f(a)b−a for some c ϵ (a,b)
Find the value of c for the function f(x) =−x2+4x-5 and the interval [-1,1]