You visited us 1 times! Enjoying our articles? Unlock Full Access!

String Fixed at Both Ends

If f1, f2, ...

Question

If $f_{1}, f_{2}, a n d f_{3}$ are the fundamental frequencies of three segments into which a string is divided, then the original fundamental frequency $f_{0}$ of the whole string is

f_{0} = f_{1} + f_{2} + f_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{f_{0}} = \frac{1}{f_{1}} + \frac{1}{f_{2}} + \frac{1}{f_{3}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{\sqrt{f_{0}}} = \frac{1}{\sqrt{f_{1}}} + \frac{1}{\sqrt{f_{2}}} + \frac{1}{\sqrt{f_{3}}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{1}{f_{0}} = \frac{1}{f_{1}} + \frac{1}{f_{2}} + \frac{1}{f_{3}}$
The original fundamental frequency is the harmonic mean.
$\frac{1}{f_{0}} = \frac{1}{f_{1}} + \frac{1}{f_{2}} + \frac{1}{f_{3}}$
This happens because we sum up the individual wavelengths and equate it to the final wavelength.
$λ = \frac{v}{f}$

Suggest Corrections

Similar questions

f (x) = x^{3} + x^{2} f^{'} (1) + x f^{''} (2) + f^{'''} (3)

x ϵ R

f (x) = 2 x - 1

x > 1

= x^{2} + 1

- 1 \leq x \leq 1

\frac{f (1) + f (3) + f (0)}{f (2) + f (- 1) + f (\frac{1}{2})}

f_{1}

f_{2}

f_{3}

f (x)

f (1) = 1, f (2) = 2, f (3) = 3

f (4) = 16

f (0)

f_{1}

f_{2}

f_{3}

f_{1} : f_{2} : f_{3}

Join BYJU'S Learning Program