The correct options are
A Set of first 10 whole numbers
C Set of even integers
Since, function is defined as f:{1,3,4}→C, the image of each and every element of {1,3,4} should be in C.
f(1)=(1)2−3(1)+2=0
f(3)=(3)2−3(3)+2=2
f(4)=(4)2−3(4)+2=6
So, co-domain can be any set consisting 0,2,6 as their elements.
Set of first 10 whole numbers is {0,1,2,3,4,5,6,7,8,9}
0,2,6∈{0,1,2,3,4,5,6,7,8,9}
Set of factors of 6 is {1,2,3,6}
0∉{1,2,3,6}
Set of even integers is {0,±2,±4,±6,...}
0,2,6∈{0,±2,±4,±6,...}
Set of natural numbers is {1,2,3,4,...}
0∉{1,2,3,4,...}