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Divisibility by 5

If f 2=0, the...

Question

If f(2) =0, then f(x) is divisible by(x-2).

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Solution

Converse If f(x) is divisible by (x-2), then f(2)=0.

Contrapositive If f(x) is not divisible by (x-2), then f(2) is not equal to 0.

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Similar questions

f (0) = 0, f (1) = 1, f (2) = 2

f (x) = f (x - 2) + f (x - 3)

x = 3, 4, 5.....

f (9) = ?

Q. The graph of the function

y = f (x)

is symmetrical about line

x = 2,

f (x) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} x - 5; x \leq 1 4 x^{2} - 9; 1 < x \leq 2 3 x^{2} + 4; x > 2 \end{matrix}

f (2^{+}) - f (2^{-}) =

f (x) = 2 x^{4} - 7 x^{3} + a x + b

is divisible by

(x - 1)

(x - 2)

(a, b) =

f (x + y) = f (x) f (y) \forall x, y \in R

f^{'} (0) = 5, f (2) = 6

f^{'} (2)

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Divisibility by 5

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