If f 22 - 0-39- f 23 - 0-41-f 24 - 0-43- f25 - 0-44 and f26 - 0-46 then -2622fxdx Using Simpsons rule is

The correct option is B 1.7 nbsp;∫ _ 22 ^ 26 f( x ) dx = 1 / 3 [ 0.85+2( 0.43 ) +4( 0.85 ) nbsp;] nbsp;= 1 / 3 ( 5.11 ) =1.7 ...

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Formation of an Expression

If f 22 = 0....

Question

If f (22) $=$ 0.39, f (23) $=$ 0.41,f (24) $=$ 0.43, f(25) $=$ 0.44 and f(26) $=$ 0.46 then $\int_{22}^{26} f (x) d x$ Using Simpsons rule is

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x:	0	0.25	0.5	0.75	1
f(x):	1	0.8	0.67	0.57	0.5

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