Question

If $f=(-2,4),(0,6),(2,8)$ and $g=(-2,-1),(0,3),(2,5)$, then $(\frac{2f}{3g}+\frac{3g}{2f})\left(0\right)=$

• A. 1/12
• B. 25/12
• C. 5/12
• D. 13/12

Answer 1

The correct option is B 25/12

$f=(-2,4),(0,6),(2,8)$

$g=(-2,-1),(0,3),(2,5)$

$(\frac{2f}{3g}+\frac{3g}{2f})\left(0\right)$

$=\frac{2f\left(0\right)}{3g\left(0\right)}+\frac{3g\left(0\right)}{2f\left(0\right)}$

$=\frac{2\times 6}{3\times 3}+\frac{3\times 3}{2\times 6}$

$=\frac{12}{9}+\frac{9}{12}$

$=\frac{4}{3}+\frac{3}{4}$

$=\frac{25}{12}$

option $B$ is correct.