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Question

If f(2x+y8,2x−y8)=xy then f(x,y)+f(y,x)=

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Solution

The correct option is A 0
f(2x+y8,2xy8)=xy
Put h=2x+y8,k=2xy8
x=12(h+k),y=4(hk)
f(h,k)=2(h2k2)
f(x,y)+f(y,x)=2(x2y2)+2(y2x2)=0

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