If f(3x+2)+f(3x+29)=0∀x∈R, then the period of f(x) is
A
7
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B
8
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C
10
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D
none of these
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Solution
The correct option is D none of these f(3x+2)+f(3x+29)=0 Replace 3x by x ⇒f(x+2)+f(x+29)=0⇒(1) Replace x by x+27 ⇒f(x+29)+f(x+56)=0⇒(2) Thus from (1) and (2) f(x+2)=f(x+56) Replace x by x−2 ⇒f(x)=f(x+54) Hence period of f is 54