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Question

If f(a)=2,f(a)=1,g(a)=1 and g(a)=2. Find the value of limxag(x)f(a)g(a)f(x)(xa)

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Solution

limxag(x)f(a)g(a)f(x)1 [using L'Hospital rule]

=g(a)f(a)g(a)f(a)

=(2)(2)(1)(1)=4+1=5

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