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Question

If f: A→B and g:B→C are onto , then gof:A→C is:


A

a bijective function

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B

a many-one and onto function

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C

a many-one and onto function

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D

an into function

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Solution

The correct option is C

a many-one and onto function


Let c∈C

g:B→C is onto

⇒c∈Chas a pre image

⇒There exists a b ∈B such that g(b) = c

b ∈B and f: A→B is onto

⇒ b∈ B has a pre image

⇒There exists an a ∈A such that f(a) = b

c = g(b) = g[f(a)] = gof (a)

So, c∈Chas a pre image a∈A , such that gof(a) = c

→gof is an onto function


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