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Question

If f and g are continuous on [0, a] and satisfy f(x) = f(a - x) and g(x) + g(x - a) = 2, then a0f(x) g(x) dx is equal to

A
a0f(x) dx
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B
a0f(ax) dx
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C
a0f(ax) g(ax) dx
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D
a0g(x) dx
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Solution

The correct option is C a0f(ax) g(ax) dx
a0f(x) dx=a0f(ax) dxa0f(x)g(x) dx =a0f(ax)g(ax) dxa0f(x)g(x) dx =a0f(ax)(2g(x)} dxa0f(x)g(x) dx =2a0f(x) dxa0f(x)g(x) dx2a0f(x)g(x) dx =2a0f(x) dxa0f(x)g(x) dx =a0f(x) dx

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