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Question

If f and g are functions such that fog is onto then

A
f is onto
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B
g is onto
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C
gof is onto
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D
Neither f nor g is onto
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Solution

The correct option is A f is onto
Given that, fog is onto.
Range(fog(x))=Codomain f(g(x))
Range of fog(x)= Codomain of f(x)...(1)
Since Range of f(x) Range of fog(x) and
Range of f(x) Codomain of f(x),
Using (1) we get Range of f(x)=Codomain of f(x).
Hence, f(x) is onto.
105610_10992_ans_1fbd9b750d8644aea4817601fdea4059.png

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