If f and g are two functions defined as f(x)=x+2,x≤0;g(x)=3,x≥0,then the domain of f+g is
{0}
[0,∞)
(-∞,∞)
(-∞,0)
To find out about the domain off+g:
f(x)=x+2,x≤0g(x)=3,x≥0
Domain of f(x)=(-∞,0]
Domain of g(x)=[0,∞)
Domain of (f+g)=(-∞,0]∩[0,∞)
={0}
Hence, option A is the correct is the answer.
If f, g, h are real functions defined by f(x)=√x+1,g(x)=1x and h(x)=2x2−3, then find the values of (2f + g - h) (1) and (2f + g - h) (0).
If f(x) , g(x) and h(x) are three differentiable functions throughout their domains and given that their first derivatives are -
f′(x)<0
g′(x)=0
h′(x)≤0
throughout their domains. Then choose the correct option of monotonically decreasing functions -