If f be decreasing continuous function satisfying fx - y - fx - fy - fx fy - x- y- R- f- 0 - -1- then -10fxdx is

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Strictly Decreasing Functions

If f be decre...

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If f be decreasing continuous function satisfying $f (x + y) = f (x) + f (y) - f (x) f (y) \forall x, y \in R$ ; $f^{'} (0) = - 1$ , then $\int_{0}^{1} f (x) d x$ is

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Similar questions

f (x + y) = f (x) + f (y) - f (x) f (y)

\forall

\in

R

f (0) \neq 0

\int_{0}^{1} f (x) d x

f^{'} (0) = 2

f (x + y) = \frac{f (x) + f (y)}{1 - f (x) f (y)}

f (π / 8)

f

f (x) f (y) = f (x) + f (y) + f (x y) - 2

x, y \in R

f (2) = 5

{lim}_{x \to 4} f (x)

f : R \to R^{+}

f (x + y) = f (x) f (y) \forall x, y ϵ R .

f^{'} (0) = 2

\forall x, y ϵ R

f^{'} (x) =

^{'} f^{'}

f (x) + f (y) = f (x + y + x y) + x y

x, y > - 1

f^{'} (0) = 0

\frac{1}{f^{''} (2)}

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