Iff:C→C is defined by f(z)=¯¯¯z (Where ¯¯¯z is the conjugate of z) then f(z) is
Let C be the set of complex numbers. Prove that the mapping f:C→R given by f(z)=|z|, ∀z∈C, is neither one-one nor onto.
Let A={x:−1≤x≤1} and f:A→A is a function defined by f(x)=x|x|, then f is
If f(z)=7−z1−z2,wehre z=1+2i,then |f(z)| is