Question

If $F=\frac{9}{5}C+32$. Find C, when $F={86}^o$.

• A. ${40}^o$
• B. ${20}^o$
• C. ${30}^o$
• D. ${25}^o$

Answer 1

The correct option is C ${30}^o$

Given equation is: $F=\frac{9}{5}C+32$

$86=\frac{9}{5}\left(C\right)+32$

$86-32=\frac{9}{5}C$

$5(86-32)=9C$

$270=9C$

$\therefore C={30}^{\circ }$