Question

If $F_g$ and $F_e$ are gravitational and electrostatic forces between two electrons at a distance $0.1m$ then $F_g/F_e$ is in the order of

• A. ${10}^{43}$
• B. ${10}^{-43}$
• C. ${10}^{35}$
• D. ${10}^{-35}$

Answer 1

The correct option is A ${10}^{43}$

$\frac{F_e}{F_g}=\frac{q_1{q}_2}{4\pi {ϵ}_0{r}^2}/\frac{G{m}_1{m}_2}{r^2}$

$\frac{F_e}{F_g}=\frac{q^2}{4\pi {ϵ}_{0}G{m}^2}$

$\frac{F_e}{F_g}=\frac{9\times {10}^9\times (1.6\times {10}^{-19}{)}^2}{6.67\times {10}^{-11}\times (9.1\times {10}^{-31}{)}^2}=0.417\times {10}^{43}$