If f,g are invertible functionsgiven by f(x)=3x−2 and (gof)−1(x)=x−2, then
A
g(x)=x+82
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B
g(x)=x−83
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C
g(x)=x+83
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D
g(x)=2x+83
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Solution
The correct option is Cg(x)=x+83 f(x)=3x−2 ⇒f−1(x)=x+23
We know that, (gof)−1(x)=f−1og−1(x)
So, (gof)−1(x)=x−2 ⇒f−1og−1(x)=x−2 ⇒f−1(g−1(x))=x−2 ⇒g−1(x)+23=x−2 ⇒g−1(x)=3x−8
Inverse function for g−1(x)=g(x)=x+83