If f is a bijective function such that fx- x-ax- and if f-1x-fx- then

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Inequalities of Integrals

if f is a b...

Question

if $f$ is a bijective function such that $f (x) = \frac{λ x + μ}{a x + β}$ and if $f^{- 1} (x) = f (x)$ , then

λ = β

α = μ = 0

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α = μ = 1

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α + β = 1

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{cos}^{- 1} (\frac{λ}{β}) = \frac{π}{4}

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Solution

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Similar questions

| s i n^{- 1} x | + | t a n^{- 1} x | + | c o s^{- 1} x | = | π - c o t^{- 1} x |

[α, β]

α a n d β

If α \leq 2 \sin^{- 1} x + \cos^{- 1} x \leq β, then (a) α = - \frac{π}{2}, β = \frac{π}{2} (b) α = 0, β = π (c) α = - \frac{π}{2}, β = \frac{3 π}{2} (d) α = 0, β = 2 π

α \leq 2 {sin}^{- 1} x + {cos}^{- 1} x \leq β,

A = {1, 2, 3}, B = {α, β, λ} C = {p, q, r}

f : A \to B, g : B \to C

f = {(1, α), (2, λ) (3, β)}

g = {(α, q), (β, r), (λ, p)}

f

g

{(g o f)}^{- 1} = f^{- 1} o g^{- 1}

f : R - {- 1, k} \to R - {α, β}

f (x) = \frac{(2 x - 1) (2 x^{2} - 4 p x + p^{3})}{(x + 1) (x^{2} - p^{2} x + p^{2})}

p \geq 0,

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