Question

If $F$ is the force, $\mu$ is the permeability, $H$ is the intensity of magnetic field and $i$ is the electric current, then $\frac{F}{\mu Hi}$ has the dimensions of :

• A. mass
• B. length
• C. time
• D. energy

Answer 1

Answer: (B)

length

$F=M^1{L}^1{T}^{-2}$
$i=I^1$
$\mu =M^1{L}^1{T}^{-2}{I}^{-2}$
$H=L^{-1}{I}^1$
$\frac{F}{\mu HI}=\frac{M^1{L}^1{T}^{-2}}{\left(M^1{L}^1{T}^{-2}{I}^{-2}\right)\left(L^{-1}{I}^1\right)\left(I^1\right)}$
$=M^0{L}^1{T}^0{I}^0$

Unit Of length