Question

If F is the force, S is the displacement and V is the velocity of the particle, the dimensions of the ratio $FS/V^2$ will be

• A. $M^{o}L{T}^o$
• B. $M{L}^o{T}^o$
• C. $M^o{L}^{o}T$
• D. $M^o{L}^o{T}^o$

Answer 1

The correct option is B $M{L}^o{T}^o$

The dimensions of the force is $F=ML{T}^{-2}$

Since S is the displacement. so, it has dimensions $S=\left[L\right]$

The dimensions of the velocity is $V=\left[L{T}^{-1}\right]$

$\frac{FS}{V^2}=\frac{M{L}^2{T}^{-2}}{L^2{T}^{-2}}=M{L}^0{T}^0$

Option $\text{B}$ is the correct answer