CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Range

If fx-4x+2=...

Question

If $f (\frac{x - 4}{x + 2}) = 2 x + 1, (x \in R - 1, - 2)$ , then $\int f (x) d x$ is equal to:
(where $C$ is constant of integration)

A

12 {log}_{e} | 1 - x | + 3 x + C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

- 12 {log}_{e} | 1 - x | - 3 x + C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

12 {log}_{e} | 1 - x | - 3 x + C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

- 12 {log}_{e} | 1 - x | + 3 x + C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $12 {log}_{e} | 1 - x | - 3 x + C$
answer is C

Suggest Corrections

thumbs-up

0

Similar questions

f (\frac{x - 4}{x + 2}) = 2 x + 1, (x \in R - {1, - 2}),

\int f (x) d x

is equal to :
(where

C

is a constant of integration)

f (\frac{x - 4}{x + 2}) = 2 x + 1, (x ϵ R = {1, - 2})

\int f (x) d x

is equal to:
(where

C

is a constant of integration)

\int \frac{x + 1}{\sqrt{2 x - 1}} d x = f (x) \sqrt{2 x - 1} + C

C

is a constant of integration, then

f (x)

f (\frac{3 x - 4}{3 x + 4}) = x + 2, x \neq - \frac{4}{3}

\int f (x) d x = A log | 1 - x | + B x + C

, then the ordered pair

(A, B)

is equal to (where C is a constant of integration)

f (\frac{x - 4}{x + 2}) = 2 x + 1, (x ϵ R = 1, - 2)

\int f (x) d x

is equal to (where

C

is a constant of integration )

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Plantae

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon