Question

If $f\left(x\right)=2x^2+3x-5$, then what is $f^{\prime }\left(0\right)+3f^{\prime }(-1)$ equal to?

• A. $-1$
• B. $0$
• C. $1$
• D. $2$

Answer 1

Answer: (B)

$0$

$f\left(x\right)=2x^2+3x-5$

$\Rightarrow f^{\prime }\left(x\right)=4x+3$

$f^{\prime }\left(0\right)=4\times 0+3=3f^{\prime }(-1)=4(-1)+3=-1$

So, $f^{\prime }\left(0\right)+3f^{\prime }(-1)=3+3(-1)=0$