Question

If $f\left(x\right)=2x^2+5\sqrt{x+2}$, complete the following statement $f\left(2\right)=\_\_\_$

Answer 1

To find the value of $f\left(2\right)$:

Consider the given function.

$f\left(x\right)=2x^2+5\sqrt{x+2}$

Substitute $x=2$:

$\begin{array}{rcl}f\left(2\right)& =& 2{\left(2\right)}^2+5\sqrt{2+2}\left[\text{Substitute}x=2\right]\\ & \Rightarrow & f\left(2\right)=2\left(4\right)+5\sqrt{4}\left[\text{Simplifying}\right]\\ & \Rightarrow & f\left(2\right)=8+5\times 2\\ & \Rightarrow & f\left(2\right)=8+10\\ \therefore f\left(2\right)& =& 18\end{array}$

Hence, the value of $f\left(2\right)$ is $\mathbf{18}$.