If f x - sin - 1x - tan - 1x- - 2-x then the range of fx is

The correct option is D [ 0,114] ...

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Range of a Function

If f x = si...

Question

If $f (x) = \frac{({sin}^{- 1} x + {tan}^{- 1} x)}{π} + 2 \sqrt{x}$ then the range of f(x) is

[- 1, 1]

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[0, 48]

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[0, \frac{15}{4}]

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[0, \frac{11}{4}]

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Solution

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Similar questions

	List I		List II
A.	Range of $f (x) = {sin}^{- 1} x + {cos}^{- 1} x + {cot}^{- 1} x$ is	1.	$[0, \frac{π}{2}) \cup (\frac{π}{2}, π]$
B.	Range of $f (x) = cot - 1 x + {tan}^{- 1} x + c o s e c^{- 1} x$ is	2.	$[\frac{π}{2}, \frac{3 π}{2}]$
C.	Range of $f (x) = {cot}^{- 1} x + {tan}^{- 1} x + {cos}^{- 1} x$ is	3.	${0, π}$
D.	Range of $f (x) = {sec}^{- 1} x + c o s e c^{- 1} x + {sin}^{- 1} x$ is	4.	$(\frac{π}{2}, \frac{3 π}{2})$