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Question

If f(x)=sin(a+1)x+2sinxx,x<0 =2,x=0 =1+bx1x,x>0
is continuous at x=0, then find the values of a and b.

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Solution

At x=0 function is continuous,
limx0+f(x)=limx0f(x)=f(0)
RHL:
=limx0+f(x)=limx0f(0+h)=limx01+bh1h×1+bh+11+bh+1
=limx01+bh1h(1+bh+1)
limx0bhh(1+bh+1)
=limx0b1+bh+1
=b2
f(0)=2
LHL:
=limx0f(x)=limh0f(0h)
=limh0sin(a+1)(0h)+sin(0h)0h
=limh0sin(a(a+1)h)+sin(h)h
=limh0sin(a+1)hh+2sinhh
=(a+1)+2
a+3=2a=1;b2=2b=4

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