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Question

If f(x)=x2−10x+25x2−7x+10 for x≠5 and f is continuous at x = 5, then f(5) has the value equal to-

A
0
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B
5
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C
10
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D
25
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Solution

The correct option is C 0
f(x)=x210x+25x27x+10f(x)=(x5)2(x5)(x2)f(x)=x5x2f(5)=0

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