Question

If $f\left(x\right)=x^2+\frac{1}{x^2}$, then find the value of $f\left(5\right)$.

Answer 1

We have,

$f\left(x\right)=x^2+\frac{1}{x^2}$

Put $x=5$

So,

$f\left(5\right)=5^2+\frac{1}{5^2}$

$=25+\frac{1}{25}$

$=\frac{626}{25}$

Hence, this is the answer.