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Question

If f(x)=x3+3x22x+4, find f(2)+f(2)f(0)

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Solution

f(x)=x3+3x22x+4
f(2)=(2)3+3×(2)22×(2)+4
=8+3×42×2+4
=8+12+4+4
=12
f(2)=23+3×222×2+4
=8+3×44+4
=8+12
=20
f(2)+f(2)f(0)=12+204
=324
=28

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