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Question

If f:RR satisfies f(x+y)=f(x)+f(y), for all x,yR and f(1)=7 ,then nr=1f(r) is


A

7n(n+1)2

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B

7n2

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C

7(n+1)2

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D

7n+(n+1)

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Solution

The correct option is A

7n(n+1)2


f(x+y)=f(x)+f(y)Function should be f(x)=mxF(1)=7; m=7,f(x)=7xnr=1f(r)=7n1r=7n(n+1)2


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