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Question

If f:R(,a] defined by f(x)=x2+6x+15 is surjective, then the value of a is

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Solution

y=f(x)=x2+6x+15
x26x(15y)=0
Since x is real, D0
36+4(15y)0
4y96
y24
Range of f is (,24]
Given, f is surjective.
Range = Codomain
a=24

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