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Question

if f:NN is defined by f(n)=n(1)n, then


A

f is one-one but not onto

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B

f is both one-one and onto

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C

f is neither one-one nor onto

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D

f is onto but not one-one

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Solution

The correct option is B

f is both one-one and onto


12, 2134, 4356, 65i.e., 2m1 2m and 2m 2m1
So, f is one-one and onto.


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