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Question

If fn(θ)=cosθ2+cos2θ+cos7θ2++cos(3n2)θ2sinθ2+sin2θ+sin7θ2++sin(3n2)θ2, then which among the following is (are) CORRECT?

A
f1(π2)=1
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B
f3(3π16)=2+1
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C
f3(3π16)=21
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D
f5(π28)=2+1
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Solution

The correct option is D f5(π28)=2+1
cosθ2+cos2θ+cos7θ2++cos(3n2)θ2=cosθ2+cos(θ2+3θ2)+cos(θ2+2(3θ2))++cos(θ2+(n1)(3θ2))
=sinn(3θ4)sin(3θ4)×⎢ ⎢ ⎢cos⎜ ⎜ ⎜θ+(n1)3θ22⎟ ⎟ ⎟⎥ ⎥ ⎥

Similarly, sinθ2+sin2θ+sin7θ2++sin(3n2)2θ=sinn(3θ4)sin(3θ4)×[sin((3n1)θ4)]
fn(θ)=cot(3n1)θ4
f1(π2)=cotπ4=1
f3(3π16)=cot2(3π16)=21
f5(π28)=cot(144(3π16))=cotπ8=2+1

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